Math

Sphere Volume and Surface Area Calculator

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A sphere is a perfectly round three-dimensional solid where every point on the surface is equidistant from the center. Enter the radius (r) below to instantly compute two fundamental properties: - Volume (V = 4/3 · π · r³) — how much space the sphere encloses - Surface Area (A = 4 · π · r²) — the total area of its outer shell Use any unit (cm, m, inches, feet) — just be consistent. These formulas apply everywhere: basketballs, water tanks, planets, soap bubbles.

Last reviewed: June 3, 2026 Verified by Source: Archimedes, On the Sphere and Cylinder (~250 BCE) — original derivation of sphere volume and surface area formulas, NIST – Physical Measurement Laboratory: SI Units and Volume Conversions, Wikipedia – Sphere: Mathematical Properties and Formulas 100% private

For a sphere of radius r: Volume = (4/3) × π × r³ and Surface Area = 4 × π × r². Example: r = 5 cm → Volume = 523.6 cm³, Surface Area = 314.2 cm². Doubling the radius multiplies volume by 8 and surface area by 4.

When to use this calculator

  • Finding the capacity of a spherical water tank or storage vessel (convert cm³ to liters by dividing by 1,000).
  • Estimating the amount of paint or material needed to coat a spherical surface — a dome, ball, or globe.
  • Solving geometry homework or standardized test problems (SAT, ACT, AP Calculus) involving spheres.
  • Engineering: computing the mass of a solid metal sphere from V × density (e.g., steel ≈ 7.85 g/cm³).
  • Science: estimating the volume or surface area of planets, cells, or fluid droplets given their radius.

Worked Example — Basketball

  1. NBA basketball radius ≈ 4.70 in
  2. V = (4/3) × π × (4.70)³ = (4/3) × π × 103.82 ≈ 434.9 in³
  3. A = 4 × π × (4.70)² = 4 × π × 22.09 ≈ 277.6 in²
Result: V ≈ 434.9 in³, A ≈ 277.6 in²

How it works

2 min read

Formulas

The two core formulas for a sphere of radius r were proven by Archimedes (~250 BCE):

Volume:       V = (4/3) · π · r³
Surface Area: A = 4 · π · r²

Where:
  r = radius (= diameter / 2)
  π ≈ 3.14159265358979

If you know the diameter (d):

V = (π · d³) / 6
A = π · d²

If you know the circumference (C):

r = C / (2π)

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Reference Table — Volume & Surface Area by Radius

Radius (cm)Diameter (cm)Volume (cm³)Surface Area (cm²)
124.1912.57
2433.5150.27
36113.10113.10
48268.08201.06
510523.60314.16
612904.78452.39
7141,436.76615.75
8162,144.66804.25
9183,053.631,017.88
10204,188.791,256.64
153014,137.172,827.43
204033,510.325,026.55
255065,449.857,853.98
3060113,097.3411,309.73
50100523,598.7831,415.93

> Tip: For r = 3 cm, volume and surface area are numerically equal (both ≈ 113.10) — a curious coincidence, not a general rule.

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Worked Examples

Example 1 — Basketball (r = 4.70 in)


V = (4/3) · π · (4.70)³ ≈ 434.9 in³
A = 4 · π · (4.70)² ≈ 277.6 in²

Example 2 — Spherical Water Tank (r = 2 m)


V = (4/3) · π · 8 ≈ 33.51 m³ → 33,510 liters ≈ 8,850 US gallons
A = 4 · π · 4 ≈ 50.27 m²

Example 3 — Steel Ball Bearing (r = 1.5 cm, ρ = 7.85 g/cm³)


V = (4/3) · π · (1.5)³ ≈ 14.137 cm³
Mass = 14.137 × 7.85 ≈ 111.0 g
A = 4 · π · (1.5)² ≈ 28.27 cm²

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Common Mistakes

1. Radius vs. diameter confusion. Entering the diameter (e.g., 10 cm) instead of the radius (5 cm) inflates volume by because r is cubed. Always halve the diameter first.

2. Forgetting the 4/3 coefficient. V = πr³ is wrong. The correct formula has a 4/3 factor (≈ 1.3333), and omitting it understates volume by ~25%.

3. Mixing units. If r is in mm but you want cm³, convert first (1 cm = 10 mm). Volume scales by the cube: 1 cm³ = 1,000 mm³.

4. Rounding π too early. π ≈ 3.14 gives ~0.05% error, which compounds when cubing. Use at least 5 decimal places (3.14159) for engineering work.

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Related Calculators

  • Circle Area & Circumference Calculator

  • Cylinder Volume & Surface Area Calculator

  • Cone Volume & Surface Area Calculator

  • Cube Volume & Surface Area Calculator

  • Frequently asked questions

    What is the formula for the volume of a sphere?

    V = (4/3) · π · r³, where r is the radius. For r = 5 cm: V = (4/3) × π × 125 ≈ 523.6 cm³. This formula was proven by Archimedes around 250 BCE using the method of exhaustion.

    What is the formula for the surface area of a sphere?

    A = 4 · π · r². For r = 5 cm: A = 4 × π × 25 ≈ 314.16 cm². This equals exactly four times the area of a great circle (πr²) — a relationship Archimedes proved in On the Sphere and Cylinder.

    How do I calculate sphere volume from the diameter?

    Divide the diameter by 2 to get the radius, then apply V = (4/3)πr³. Or use the direct formula V = (π · d³) / 6. For d = 12 cm: V = π × 1728 / 6 ≈ 904.78 cm³.

    How do I convert sphere volume from cm³ to liters or gallons?

    Use: 1 liter = 1,000 cm³ and 1 US gallon = 3,785.41 cm³. A sphere with r = 20 cm has V ≈ 33,510 cm³ = 33.51 liters8.85 US gallons.

    Does doubling the radius double the volume?

    No — volume scales with , so doubling the radius multiplies volume by 2³ = 8. Example: r = 5 cm → V ≈ 523.6 cm³; r = 10 cm → V ≈ 4,188.8 cm³ (8× larger). Surface area scales with r², so doubling r increases it by .

    What is the relationship between a sphere and its enclosing cylinder?

    A sphere of radius r fits inside a cylinder of radius r and height 2r. The sphere's volume is exactly 2/3 of the cylinder's volume (2πr³). Archimedes considered this ratio his greatest discovery and asked for it to be inscribed on his tomb.

    Can I use this calculator for hollow spheres (spherical shells)?

    For a hollow sphere with outer radius R and inner radius r: shell volume = (4/3)π(R³ − r³) and surface area = 4π(R² + r²) (both surfaces). Run this calculator twice and subtract the volumes — or add the two surface areas.

    What are some real-world examples where sphere formulas are used?

    Basketball sizing (NBA diameter ≈ 9.39 in, V ≈ 434.9 in³), spherical water tanks (r = 2 m holds ~33,510 liters), steel ball bearings (r = 1.5 cm, mass ≈ 111 g), planetary science (Earth's mean radius ≈ 6,371 km, V ≈ 1.083 × 10¹² km³), and soap bubbles (minimizing surface area for a given volume is why they are spherical).

    Why is π (pi) used in the sphere formulas?

    π appears because spheres are inherently circular — every cross-section through the center is a circle of area πr². Volume integrates infinitely many such circles, and surface area is the limiting case of many small circular patches. π ≈ 3.14159265... is irrational and transcendental, so all sphere volumes/areas involving exact dimensions are also irrational.

    Sources and references